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9-m^2=6m
We move all terms to the left:
9-m^2-(6m)=0
We add all the numbers together, and all the variables
-1m^2-6m+9=0
a = -1; b = -6; c = +9;
Δ = b2-4ac
Δ = -62-4·(-1)·9
Δ = 72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{72}=\sqrt{36*2}=\sqrt{36}*\sqrt{2}=6\sqrt{2}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6\sqrt{2}}{2*-1}=\frac{6-6\sqrt{2}}{-2} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6\sqrt{2}}{2*-1}=\frac{6+6\sqrt{2}}{-2} $
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